1) The diagonal of a square is 16 cm. Find its side.(A)82 cm (B)16v2 cm (C8y4 cm(D)164 cmcm About the author Charlie
Answer: Step-by-step explanation: all the angles of a square is right angle therefore the diagonal forms the hypotenuse of the 2 sides therefore by Pythagoras theorem , [tex]side^{2} +side^{2} = hypotenuse^{2}[/tex] therefore let the side of square be x [tex]x^{2} +x^{2} =16^{2}[/tex] 2[tex]x^{2}[/tex] =[tex]16^{2}[/tex] [tex]2x^{2} =256[/tex] [tex]x^{2} =128[/tex] [tex]x=\sqrt 128[/tex] [tex]x = 8\sqrt2[/tex] pls mark me as brainliest and give 5 stars and thank me Reply
Answer:
Step-by-step explanation:
all the angles of a square is right angle therefore the diagonal forms the hypotenuse of the 2 sides
therefore by Pythagoras theorem ,
[tex]side^{2} +side^{2} = hypotenuse^{2}[/tex]
therefore let the side of square be x
[tex]x^{2} +x^{2} =16^{2}[/tex]
2[tex]x^{2}[/tex] =[tex]16^{2}[/tex]
[tex]2x^{2} =256[/tex]
[tex]x^{2} =128[/tex]
[tex]x=\sqrt 128[/tex]
[tex]x = 8\sqrt2[/tex]
pls mark me as brainliest and give 5 stars and thank me