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1. Let X and Y be two independent random variables with Var(X)=9 and Var(Y)=3 then Var(4X-
2Y+6) is
d)256
By Iris

1. Let X and Y be two independent random variables with Var(X)=9 and Var(Y)=3 then Var(4X-
2Y+6) is
d)256
4C9 – 20) +
c) 156
a) 9
b) 81​

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Iris

The diameter of a metallic sphere is 8cm.The sphere is melted and drawn into a wire of uniform cross-section.If the length of the

(-8/9×-6/7)‐(1/10×‐3/5)+(3/5×‐2/7)‐(8/9×‐5/11) please help me in this question ​

2 thoughts on “<br /><br />1. Let X and Y be two independent random variables with Var(X)=9 and Var(Y)=3 then Var(4X-<br />2Y+6) is<br />d)256<br”

  1. SOLUTION

    TO CHOOSE THE CORRECT OPTION

    Let X and Y be two independent random variables with Var(X) = 9 and Var(Y) = 3 then Var(4X- 2Y + 6)

    a) 9

    b) 81

    c) 156

    d)256

    FORMULA TO BE IMPLEMENTED

    We are aware of the formula on variance that

    [tex] \sf{Var(aX + bY + c) = {a}^{2}Var(X) + {b}^{2} Var(Y)}[/tex]

    EVALUATION

    Here it is given that Var(X) = 9 and Var(Y) = 3

    Now

    [tex] \sf{Var(4X – 2Y + 6) }[/tex]

    [tex] \sf{= {4}^{2}Var(X) + {( – 2)}^{2} Var(Y)}[/tex]

    [tex] \sf{= 16Var(X) + 4 Var(Y)}[/tex]

    [tex] \sf{= (16 \times 9)+ (4 \times 3)}[/tex]

    [tex] \sf{=144 + 12}[/tex]

    [tex] \sf{= 156}[/tex]

    FINAL ANSWER

    Hence the correct option is c) 156

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