1. If the sum of zeroes ofthe polynomial 2×2 + px + 11 is11/2, then what is the value of p? About the author Harper
Answer :- p = – 11 Given that :- polynomial = [tex]2x^2 +px+11[/tex] sum of zeros = [tex]\frac{11}{2}[/tex] To find :- the value of p Solution :- we know that sum of zeros = [tex]\frac{-(cofficient \ of \ x)}{cofficient \ of \ x^2}[/tex] => [tex]\frac{11}{2}=\frac{-p}{2}[/tex] => [tex]-p=11[/tex] => [tex]p=-11[/tex] May be this is helpful for you Reply
Answer :-
p = – 11
Given that :-
polynomial = [tex]2x^2 +px+11[/tex]
sum of zeros = [tex]\frac{11}{2}[/tex]
To find :-
the value of p
Solution :-
we know that
sum of zeros = [tex]\frac{-(cofficient \ of \ x)}{cofficient \ of \ x^2}[/tex]
=> [tex]\frac{11}{2}=\frac{-p}{2}[/tex]
=> [tex]-p=11[/tex]
=> [tex]p=-11[/tex]
May be this is helpful for you