1. Find the Pythagorean triplets from among the following sets of numbers. (i) 3, 4, 5(ii) 2, 4, 5(iii) 4, 5, 6(iv) 2, 6, 7(v) 9, 40, 41(vi) 4, 7, 8 About the author Quinn
Answer : (i) 3, 4, 5 = 25 (ii) 2, 4, 5 ≠ 25 (iii) 4, 5, 6 ≠ 36 (iv) 2, 6, 7 ≠ 49 (v) 9, 40, 41 = 1681 (vi) 4, 7, 8 ≠ 65 Step-by-step explanation : (i) 3, 4, 5 = 3² + 4² = 5² Sol:- 3² + 4² = 5² 9 + 16 = 25 •°• 25 = 25 (ii) 2, 4, 5 = 2² + 4² ≠ 5² Sol:- 2² + 4² ≠ 5² 4 + 16 ≠ 25 •°• 20 ≠ 25 (iii) 4, 5, 6 = 4² + 5² ≠ 6² Sol:- 4² + 5² ≠ 6² 16 + 25 ≠ 36 •°• 41 ≠ 36 (iv) 2, 6, 7 = 2² + 6² ≠ 7² Sol:- 2² + 6² ≠ 7² 4 + 36 ≠ 49 •°• 40 ≠ 49 (v) 9, 40, 41 = 9² + 40² = 41² Sol:- 9² + 40² = 41² 81 + 1600 = 1681 •°• 1681 = 1681 (vi) 4, 7, 8 = 4² + 7² ≠ 8² Sol:- 4² + 7² ≠ 8² 16 + 49 ≠ 64 •°• 65 ≠ 64 Reply
Answer :
(i) 3, 4, 5 = 25
(ii) 2, 4, 5 ≠ 25
(iii) 4, 5, 6 ≠ 36
(iv) 2, 6, 7 ≠ 49
(v) 9, 40, 41 = 1681
(vi) 4, 7, 8 ≠ 65
Step-by-step explanation :
(i) 3, 4, 5 = 3² + 4² = 5²
Sol:- 3² + 4² = 5²
9 + 16 = 25
•°• 25 = 25
(ii) 2, 4, 5 = 2² + 4² ≠ 5²
Sol:- 2² + 4² ≠ 5²
4 + 16 ≠ 25
•°• 20 ≠ 25
(iii) 4, 5, 6 = 4² + 5² ≠ 6²
Sol:- 4² + 5² ≠ 6²
16 + 25 ≠ 36
•°• 41 ≠ 36
(iv) 2, 6, 7 = 2² + 6² ≠ 7²
Sol:- 2² + 6² ≠ 7²
4 + 36 ≠ 49
•°• 40 ≠ 49
(v) 9, 40, 41 = 9² + 40² = 41²
Sol:- 9² + 40² = 41²
81 + 1600 = 1681
•°• 1681 = 1681
(vi) 4, 7, 8 = 4² + 7² ≠ 8²
Sol:- 4² + 7² ≠ 8²
16 + 49 ≠ 64
•°• 65 ≠ 64
Answer:
1st one
Step-by-step explanation:
3²+4²=5²
9+16=25