1. Find the equations of tangent and normal to the

curve y = x⁴- 6x³ + 13x² -10x + 5 at (0,5).

# 1. Find the equations of tangent and normal to the

### 1 thought on “1. Find the equations of tangent and normal to the<br />curve y = x⁴- 6x³ + 13x² -10x + 5 at (0,5).”

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Answer:At (0,5) slope of tangent is -10

Step-by-step explanation:Equation of tangent is y-5=-10x

Slope of normal at (0,5) is 1/10

Equation of normal is 10y-50=x

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