1. Find the equations of tangent and normal to the
curve y = x⁴- 6x³ + 13x² -10x + 5 at (0,5).​

by

1. Find the equations of tangent and normal to the
curve y = x⁴- 6x³ + 13x² -10x + 5 at (0,5).​

1 thought on “1. Find the equations of tangent and normal to the<br />curve y = x⁴- 6x³ + 13x² -10x + 5 at (0,5).​”

  1. Answer:

    At (0,5) slope of tangent is -10

    Step-by-step explanation:

    Equation of tangent is y-5=-10x

    Slope of normal at (0,5) is 1/10

    Equation of normal is 10y-50=x

    Please mark my answer as BRAINLIEST answer

    Hope you have a good day

Leave a Comment