1. Find the equations of tangent and normal to the
curve y = x⁴- 6x³ + 13x² -10x + 5 at (0,5).

Question

1. Find the equations of tangent and normal to the curve y = x⁴- 6x³ + 13x² -10x + 5 at (0,5).​

Arya · Answer

Answer:   At (0,5) slope of tangent is -10   Step-by-step explanation:   Equation of tangent is y-5=-10x  Slope of normal at (0,5) is 1/10  Equation of normal is 10y-50=x  Please mark my answer as BRAINLIEST answer  Hope you have a good day

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1. Find the equations of tangent and normal to thecurve y = x⁴- 6x³ + 13x² -10x + 5 at (0,5).​