(0)(a + bla
One of the factor of X6 + 10×3 – 27 is
(a) x2 – X + 3
(x²-x-3
(c) x2 + x – 3
(d) x2 + x + 3
One of the factor of x® + 10×2-271RAVAT
(0)(a + bla
2 thoughts on “(0)(a + bla<br />One of the factor of X6 + 10×3 – 27 is<br />(a) x2 – X + 3<br />(x²-x-3<br />(c) x2 + x – 3<br />(d) x2 + x + 3<b”
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Answer:
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Step-by-step explanation:
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Answer:
Given, x
6
−10x
3
−27
=x
6
−x
3
−27−9x
3
=(x
2
)
3
+(−x)
3
+(−3)
3
−3(x
2
)(−x)(−3)
Using, a
3
+b
3
+c
3
−3abc=(a+b+c)(a
2
+b
2
+c
2
−ab−ac−bc)
=(x
2
−x−3)((x
2
)
2
+(−x)
2
+(−3)
2
−(x
2
)(−x)−(x
2
)(−3)−(−x)(−3))
=(x
2
−x−3)(x
4
+x
2
+9+x
3
+3x
2
−3x)
=(x
2
−x−3)(x
4
+x
3
+4x
2
−3x+9)