(0)(a + bla
One of the factor of X6 + 10×3 – 27 is
(a) x2 – X + 3
(x²-x-3
(c) x2 + x – 3
(d) x2 + x + 3
By Arya

(0)(a + bla
One of the factor of X6 + 10×3 – 27 is
(a) x2 – X + 3
(x²-x-3
(c) x2 + x – 3
(d) x2 + x + 3
One of the factor of x® + 10×2-271RAVAT​

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Arya

2 thoughts on “(0)(a + bla<br />One of the factor of X6 + 10×3 – 27 is<br />(a) x2 – X + 3<br />(x²-x-3<br />(c) x2 + x – 3<br />(d) x2 + x + 3<b”

  1. Answer:

    Given, x

    6

    −10x

    3

    −27

    =x

    6

    −x

    3

    −27−9x

    3

    =(x

    2

    )

    3

    +(−x)

    3

    +(−3)

    3

    −3(x

    2

    )(−x)(−3)

    Using, a

    3

    +b

    3

    +c

    3

    −3abc=(a+b+c)(a

    2

    +b

    2

    +c

    2

    −ab−ac−bc)

    =(x

    2

    −x−3)((x

    2

    )

    2

    +(−x)

    2

    +(−3)

    2

    −(x

    2

    )(−x)−(x

    2

    )(−3)−(−x)(−3))

    =(x

    2

    −x−3)(x

    4

    +x

    2

    +9+x

    3

    +3x

    2

    −3x)

    =(x

    2

    −x−3)(x

    4

    +x

    3

    +4x

    2

    −3x+9)

    Reply

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