0.5 was the Magnification of an image formed on a rear view mirror When the Object was placed at a distance of 30cm.Find the image distance . Solve step by step About the author Alexandra
Answer :- Image is formed at a distance of 15 cm from the mirror. Explanation :- We have :- → Magnification = 0.5 → The mirror is a rear view mirror. → Distance of the object = 30 cm ________________________________ Since it is given that the mirror is a rear view mirror. So, it is a convex mirror. For a convex mirror :- • u = -30 cm ________________________________ Now, according to formula of magnification :- m = –(v/u) ⇒ 0.5 = -(v/-30) ⇒ 0.5 = v/30 ⇒ v = 0.5 × 30 ⇒ v = 15 cm Reply
Given :- 0.5 was the Magnification of an image formed on a rear view mirror When the Object was placed at a distance of 30cm. To Find :- Image distance Solution :- We know that m = -v/u Where m = magnification v = image distance u = object distance 0.5 = -v/u 0.5 can be written as 1/2 1/2 = -v/-30 1/2 = v/30 1(30) = 2v 30 = 2v 30/2 = v 15 = v [tex]\\[/tex] Reply
Answer :-
Image is formed at a distance of 15 cm from the mirror.
Explanation :-
We have :-
→ Magnification = 0.5
→ The mirror is a rear view mirror.
→ Distance of the object = 30 cm
________________________________
Since it is given that the mirror is a rear view mirror. So, it is a convex mirror.
For a convex mirror :-
• u = -30 cm
________________________________
Now, according to formula of magnification :-
m = –(v/u)
⇒ 0.5 = -(v/-30)
⇒ 0.5 = v/30
⇒ v = 0.5 × 30
⇒ v = 15 cm
Given :-
0.5 was the Magnification of an image formed on a rear view mirror When the Object was placed at a distance of 30cm.
To Find :-
Image distance
Solution :-
We know that
m = -v/u
Where
m = magnification
v = image distance
u = object distance
0.5 = -v/u
1/2 = -v/-30
1/2 = v/30
1(30) = 2v
30 = 2v
30/2 = v
15 = v
[tex]\\[/tex]