Zahid had invested in a bank scheme which of interested 8.6 % annual for 7.8 year how much interest will be invested for 20000 rup

Zahid had invested in a bank scheme which of interested 8.6 % annual for 7.8 year how much interest will be invested for 20000 rupees

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  1. Given:

    •Rate of interest=8.6%

    •Time is given=7.8years

    •Principal = 20000rupees

    To Find:

    •How much interest will be invested

    Solution:

    we have,

    • Principal=20000rupees
    • Rate=8.6%
    • Time=7.8years

    Using Formula:

    [tex] \: \: \sf \: simple \: interest = \frac{principal \times rate \times time}{100} [/tex]

    Now substitue the values,

    [tex] \: \: \sf \: s.i = \frac{20000 \times 86 \times 78}{100 \times 10 \times 10} \\ \\ \: \: \sf \: s.i = 2 \times 86 \times 78 \\ \\ \: \: \sf \: s.i = 13416 \: rupees[/tex]

    Henceforth,Simple Interest is 13416 rupees.

    _____________________________

    Extra Info…

    •Principal=Simple Interest *100/Rate*time

    •Time=Simple Interest*100/Principal*rate

    •Rate=Simple Interest*100/Principal*time

    •Amount=Principal+Simple Interest

    •Principal=Amount-Simple Interest

    •Simple Interest=Amount-Principal

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