Answer: Rationalizing of all terms see in attachment. Now, Get back to the question, \begin{gathered}(2 \sqrt{3} + \sqrt{6} ) + (3 \sqrt{2} – 2 \sqrt{3} ) – (3 \sqrt{2} + \sqrt{6} ) \\ \\ = 2 \sqrt{3} + \sqrt{6} + 3 \sqrt{2} – 2 \sqrt{3} – 3 \sqrt{2} – \sqrt{6} \\ \\ = \cancel{2 \sqrt{3} } + \cancel{\sqrt{6} } + \cancel{3 \sqrt{2} } – \cancel{2 \sqrt{3} } – \cancel{3 \sqrt{2} } – \cancel{\sqrt{6}} \\ \\ = 0\end{gathered}(23+6)+(32−23)−(32+6)=23+6+32−23−32−6=23+6+32−23−32−6=0 Reply
Answer:
Rationalizing of all terms see in attachment.
Now, Get back to the question,
\begin{gathered}(2 \sqrt{3} + \sqrt{6} ) + (3 \sqrt{2} – 2 \sqrt{3} ) – (3 \sqrt{2} + \sqrt{6} ) \\ \\ = 2 \sqrt{3} + \sqrt{6} + 3 \sqrt{2} – 2 \sqrt{3} – 3 \sqrt{2} – \sqrt{6} \\ \\ = \cancel{2 \sqrt{3} } + \cancel{\sqrt{6} } + \cancel{3 \sqrt{2} } – \cancel{2 \sqrt{3} } – \cancel{3 \sqrt{2} } – \cancel{\sqrt{6}} \\ \\ = 0\end{gathered}(23+6)+(32−23)−(32+6)=23+6+32−23−32−6=23+6+32−23−32−6=0