Yash scored 40 marks in a test, getting 3 marks for each right answer and losing 1
mark for each wrong answer. Had 4 marks b

By Anna

Yash scored 40 marks in a test, getting 3 marks for each right answer and losing 1
mark for each wrong answer. Had 4 marks been awarded for each correct answer
and 2 marks been deducted for each incorrect answer, then Yash would have
scored 50 marks. How many questions were there in the test?

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Anna

2 thoughts on “Yash scored 40 marks in a test, getting 3 marks for each right answer and losing 1<br /> mark for each wrong answer. Had 4 marks b”

  1. Answer:

    [tex]{ \large{ \pmb{ \sf{★Given…}}}}[/tex]

    Yash Marks in a test = 40 marks

    Mark for a correct answer = 3 marks

    Mark for wrong Answer = – 1 mark

    If,

    Mark for correct answer = 4 marks

    Mark for wrong answer = – 2 marks

    Yash Marks in test = 50 marks

    [tex]{ \large{ \pmb{ \sf{★Find… }}}}[/tex]

    Number of Questions in test?

    [tex]{ \large{ \pmb{ \sf{★Assume \: That.. }}}}[/tex]

    Number of Wrong be X

    Number of correct be Y

    [tex]{ \large{ \pmb{ \sf{★Solution… }}}}[/tex]

    According to question,

    [tex]{ \to{ \sf{3Y – X = \: 40 \:…(1) }}}[/tex]

    [tex] \to \sf{4Y – 2X = 50 …(2) }[/tex]

    Now Divide the equation (2) with 2

    [tex] \to \: { \sf{ \frac{4Y}{2} – \frac{2X}{2} = \frac{50}{2} }} \\ [/tex]

    [tex] \bold{ \to{2Y – X = 25…(3)}}[/tex]

    Now subtract (1) and (3) :

    [tex]{ \implies{ \sf{3Y – X – (2Y – X) = 40 – 25}}}[/tex]

    [tex] \: { \implies{ \sf{3Y – 2Y = 15}}}[/tex]

    [tex]{ \implies{ \sf{Y = 15}}}[/tex]

    Now Substitute Y value in equation (3):

    2Y – X = 25

    – X = 25 – 30

    X = 5

    Total Number of Questions :-

    Correct Answers (Y) = 15

    Wrong Answers (X) = 5

    Y + X = 15 + 5 = 20

    Total Questions = 20

    Therefore,

    • Total questions = 20
    Reply
  2. [tex]{\large{\underline{\pmb{\frak{Given\; that…}}}}}[/tex]

    → Yash scored 40 marks in a test , getting 3 marks for each right answer and losing 1 mark for each wrong answer.

    → Had 4 marks been awarded for each correct answer and 2 marks been deducted for each incorrect answer, then Yash would have scored 50 marks

    [tex]{\large{\underline{\pmb{\frak{To\; Find…}}}}}[/tex]

    → How many questions were there in the test??

    [tex]{\large{\underline{\pmb{\frak{Understanding \; the \; concept…}}}}}[/tex]

    Concept : here we have been provided with two statements related to the test which are that,

    ⠀⠀⠀⠀⠀Yash scored 40 marks in a test , getting 3 marks for each right answer and losing 1 mark for each wrong answer.

    ⠀⠀⠀⠀⠀ If Had 4 marks been awarded for each correct answer and 2 marks been deducted for each incorrect answer, then Yash would have scored 50 marks.

    ✰ Now let’s frame equations according to the statement assigning suitable variables to the right and the wrong answers as they are undefined and then use substitution method to solve them.

    [tex]{\large{\underline{\pmb{\sf{RequirEd \; Solution…}}}}}[/tex]

    ★ There were 20 questions in total in the test conducted⠀⠀⠀⠀⠀

    [tex]{\large{\underline{\pmb{\frak{Full \; solution..}}}}}[/tex]

    ✪ Now let’s assume that,

    ⠀⠀⠀» The number of right answers = x

    ⠀⠀⠀» The number of wrong answers = y

    ⋆ According to condition 1,

    → Marks awarded for right answers = 3x

    → Marks awarded for wrong answers = – 1 y

    ~ Framing an equation according to condition 1

    [tex]\longrightarrow \tt 3x – y = 40 —(1)[/tex]

    ⋆ According to condition 2,

    → Marks awarded for right answers = 4x

    → Marks awarded for wrong answers = -2y

    ~ Framing an equation according to condition 2,

    [tex]\longrightarrow \tt 4x – 2y = 50 —(2)[/tex]

    ~ From equation one let’s find out the value of y in terms of the variable x

    [tex]\longrightarrow \tt 3x – y = 40[/tex]

    [tex]\longrightarrow \tt y = 3x – 40[/tex]

    ~ Now let’s substitute the value of y in equation 2 and find the value of x

    [tex]\longrightarrow \tt 4x – 2y = 50[/tex]

    [tex]\longrightarrow \tt 4x – 2( 3x – 40) = 50[/tex]

    [tex]\longrightarrow \tt4x – 6x + 80 = 50[/tex]

    [tex]\longrightarrow \tt – 2x = 50 – 80[/tex]

    [tex]\longrightarrow \tt – 2x = – 30[/tex]

    [tex]\longrightarrow \tt x = -30/-2[/tex]

    [tex]\longrightarrow \tt x = 15[/tex]

    • Henceforth the number of correct questions answered by him are 15

    ~ Now let’s find the value of y by putting the value of x in equation 1

    [tex]\longrightarrow \tt 3x – y = 40[/tex]

    [tex]\longrightarrow \tt 3(15) – y = 40[/tex]

    [tex]\longrightarrow \tt 45 – y = 40[/tex]

    [tex]\longrightarrow \tt y = 45 – 40[/tex]

    [tex]\longrightarrow \tt y = 5[/tex]

    • Henceforth the no.of incorrect questions answered by him are 5

    ~ Now let’s find the total number of questions answered by him

    → Total no.of questions = x + y

    → Total no.of questions 15 + 5

    → Total no.of questions = 20

    • Henceforth the number of questions in the test are 20
    Reply

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