Write the values of k for which the system of equations x + ky = 0, 2x – y = 0 hasunique solution. About the author Liliana
Answer: 3x+ky=0,2x−y=0 a 1 =3,b 1 =k and c 1 =0 a 2 =2+b 2 =−1 and c 2 =0 a 2 a 1 = 2 3 , b 2 b 1 = −1 k a 2 a 1 = b 2 b 1 ⇒ 2 3 = −1 k The system has a unique solution. k =−3/2 Step-by-step explanation: Reply
Answer:
3x+ky=0,2x−y=0
a
1
=3,b
1
=k and c
1
=0
a
2
=2+b
2
=−1 and c
2
=0
a
2
a
1
=
2
3
,
b
2
b
1
=
−1
k
a
2
a
1
=
b
2
b
1
⇒
2
3
=
−1
k
The system has a unique solution.
k
=−3/2
Step-by-step explanation: