write the number of solution of the following pair of linear equation x+2y-8=0, 2x+4y=16​

2 thoughts on “write the number of solution of the following pair of linear equation x+2y-8=0, 2x+4y=16​”

1. Step-by-step explanation:

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   x+2y=8

   And 2x+4y=16

   These given equations are in the form:

   a

   1

   x+b

   1

   y+c

   1

   =0 and

   a

   2

   x+b

   2

   y+c

   2

   =0

   Where

   a

   1

   =1,b

   1

   =2 and c

   1

   =8

   a

   2

   =2,b

   2

   =4 and c

   2

   =16

   a

   2

   a

   1

   =

   2

   1

   ,

   b

   2

   b

   1

   =

   4

   2

   =

   2

   1

   System has infinitely many solutions

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2. Answer:

   This pair of equation will have infinitely many solutions.

   Step-by-step explanation:

   This pair of equation will have infinitely many solutions.

   Because 2x + 4y = 16 can be written as x + 2y = 8 or x + 2y – 8 = 0.

   So, both these equations are actually same.

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