Step-by-step explanation: [tex]{\large{\sf{\underline{Part \: 1 :-}}}}[/tex] [tex]{\bold{\sf{Let’s \: take \: the \: integer \: be \: x \: and \: y \: }}}[/tex] [tex]{\bold{\sf{Therefore, \: x \: + \: y \: = \: 6}}}[/tex] [tex]{\bold{\sf{Suppose \: any \: number \: at \: place \: of \: x}}}[/tex] [tex]{\bold{\sf{Let’s \: take \: x \: = \: 3}}}[/tex] [tex]{\bold{\sf{Then,}}}[/tex] [tex]{\bold{\sf{→ \: 3 \: + \: y \: = \: 6}}}[/tex] [tex]{\bold{\sf{→ \: y \: = \: 6 \: -3}}}[/tex] [tex]{\bold{\sf{→ \: y \: = \: 3}}}[/tex] [tex]{\bold{\sf{\red{Therefore \: the \: pair \: of \: integer \: whose \: sum \: is \: 6 \: are \: 3 \: and \: 3}}}}[/tex] [tex] \\ {\large{\sf{\underline{Part \: 2 \: :-}}}}[/tex] [tex]{\bold{\sf{Let’s \: take \: the \: integer \: be \: a \: and \: b}}}[/tex] [tex]{\bold{\sf{Therefore, \: a \: + \: b \: = \: -8}}}[/tex] [tex]{\bold{\sf{Suppose \: any \: number \: at \: place \: of \: a}}}[/tex] [tex]{\bold{\sf{Let’s \: take \: a \: = \: -13}}}[/tex] [tex]{\bold{\sf{Then,}}}[/tex] [tex]{\bold{\sf{→ \: -13 \: + \: b \: = \: -8}}}[/tex] [tex]{\bold{\sf{→ \: b \: = \: -8 \: – \: (-13)}}}[/tex] [tex]{\bold{\sf{→ \: b \: = \: -5}}}[/tex] [tex]{\bold{\sf{\red{Therefore \: the \: pair \: of \: integer \: whose \: sum \: is \: -8 \: \: are \: -5 \: and \: -13}}}}[/tex] Reply
Step-by-step explanation:
[tex]{\large{\sf{\underline{Part \: 1 :-}}}}[/tex]
[tex]{\bold{\sf{Let’s \: take \: the \: integer \: be \: x \: and \: y \: }}}[/tex]
[tex]{\bold{\sf{Therefore, \: x \: + \: y \: = \: 6}}}[/tex]
[tex]{\bold{\sf{Suppose \: any \: number \: at \: place \: of \: x}}}[/tex]
[tex]{\bold{\sf{Let’s \: take \: x \: = \: 3}}}[/tex]
[tex]{\bold{\sf{Then,}}}[/tex]
[tex]{\bold{\sf{→ \: 3 \: + \: y \: = \: 6}}}[/tex]
[tex]{\bold{\sf{→ \: y \: = \: 6 \: -3}}}[/tex]
[tex]{\bold{\sf{→ \: y \: = \: 3}}}[/tex]
[tex]{\bold{\sf{\red{Therefore \: the \: pair \: of \: integer \: whose \: sum \: is \: 6 \: are \: 3 \: and \: 3}}}}[/tex]
[tex] \\ {\large{\sf{\underline{Part \: 2 \: :-}}}}[/tex]
[tex]{\bold{\sf{Let’s \: take \: the \: integer \: be \: a \: and \: b}}}[/tex]
[tex]{\bold{\sf{Therefore, \: a \: + \: b \: = \: -8}}}[/tex]
[tex]{\bold{\sf{Suppose \: any \: number \: at \: place \: of \: a}}}[/tex]
[tex]{\bold{\sf{Let’s \: take \: a \: = \: -13}}}[/tex]
[tex]{\bold{\sf{Then,}}}[/tex]
[tex]{\bold{\sf{→ \: -13 \: + \: b \: = \: -8}}}[/tex]
[tex]{\bold{\sf{→ \: b \: = \: -8 \: – \: (-13)}}}[/tex]
[tex]{\bold{\sf{→ \: b \: = \: -5}}}[/tex]
[tex]{\bold{\sf{\red{Therefore \: the \: pair \: of \: integer \: whose \: sum \: is \: -8 \: \: are \: -5 \: and \: -13}}}}[/tex]
Answer:
+1 +2 +3 +4 5
Step-by-step explanation:
because they are integers