Without solving, comment upon the nature of the roots of the following :
[tex]x { }^{2} – ax – b {}^{2} = 0[/tex]

Question

Without solving, comment upon the nature of the roots of the following :   x { }^{2}  - ax - b {}^{2}  = 0  ​

Josie · Answer

Step-by-step explanation:   x^2- ax - b^2 = 0  A= 1,B= -a and C= -b  .. Discriminant B^2=- 4AC  = (-a)^2 -4(1)(-b^2)  = a^2+4b^2 = a positive value.  Since a^2+ 4b^2 is not the perfect square, a  root is irrational.  Since D>0, then the equation has two  irrational and unequal roots.

Hadley

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Without solving, comment upon the nature of the roots of the following : [tex]x { }^{2} – ax – b {}^{2} = 0[/tex]​