2 thoughts on “Why is the graph of F=1/r^2 made a straight line passing through origin in physics books<br />✎﹏﹏﹏﹏﹏﹏﹏﹏﹏﹏<br /><br />thanku thanku”
This is because F is directly proportional to [tex]\frac{1}{r {}^{2} }[/tex] and since , it is directly proportional , the graph is a straight line passing through origin inclined towards the [tex]\frac{1}{r {}^{2} }[/tex] axis . Had it been the graph of [tex]F – R{}^{2}[/tex], it would have been a hyperbola , since F is inversely proportional to [tex]r{}^{2}[/tex]
[tex]\sf\blue{hope \: this \: helps \: you!! \: }[/tex]
This is because F is directly proportional to [tex]\frac{1}{r {}^{2} }[/tex] and since , it is directly proportional , the graph is a straight line passing through origin inclined towards the [tex]\frac{1}{r {}^{2} }[/tex] axis . Had it been the graph of [tex]F – R{}^{2}[/tex], it would have been a hyperbola , since F is inversely proportional to [tex]r{}^{2}[/tex]
[tex]\sf\blue{hope \: this \: helps \: you!! \: }[/tex]
@Mahor2111
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