\\ (۱) ( –whosecentre isFind the equation of the circle[2,-3] and passing through the point (1,2) About the author Vivian
Step-by-step explanation: The equation of circle be (x−h)2+(y−k)2=r2 center (−2,3) ⟹(x+2)2+(y−3)2=r2 It passes through (4,5) ⟹(4+2)2+(5−3)2=r262+22=r2r2=36+4r2=40 So the equation of circle is (x+2)2+(y−3)2=40 Reply
Step-by-step explanation:
The equation of circle be (x−h)2+(y−k)2=r2
center (−2,3)
⟹(x+2)2+(y−3)2=r2
It passes through (4,5)
⟹(4+2)2+(5−3)2=r262+22=r2r2=36+4r2=40
So the equation of circle is (x+2)2+(y−3)2=40