When numerator of a fraction is increased by 40% and denominator increased by 80% the resultant fraction becomes14/27Find the original fraction ? About the author Lyla
Answer: [tex]\bf Original \ fraction = \frac{126}{189}[/tex] Step-by-step explanation: Let the numerator=100x Denominator=100y [tex]So\ fraction\ =\frac xy[/tex] Now numerator is increased by 40% ,So numerator=140x and denominator is increased by 80% So denominator=180y [tex]Thus \ New \ Fraction= \frac{140x}{180y}= \frac{7x}{9y}\\\\Given\ that \\\\\frac{7x}{9y}\ =\frac { 14}{27}\\\\\bf \frac xy = \frac { 14\times 9}{27 \times 7}=\frac{126}{189}[/tex] Reply
Answer:
[tex]\bf Original \ fraction = \frac{126}{189}[/tex]
Step-by-step explanation:
Let the numerator=100x
Denominator=100y
[tex]So\ fraction\ =\frac xy[/tex]
Now numerator is increased by 40% ,So numerator=140x
and denominator is increased by 80%
So denominator=180y
[tex]Thus \ New \ Fraction= \frac{140x}{180y}= \frac{7x}{9y}\\\\Given\ that \\\\\frac{7x}{9y}\ =\frac { 14}{27}\\\\\bf \frac xy = \frac { 14\times 9}{27 \times 7}=\frac{126}{189}[/tex]