When a bucket is filled 3/8 of its capacity its weight is 10 Kg. If it is filled 3/5 of its capacity, its weight is 14.5 kg. How much will its weight be when it is filled to the full capacity ? About the author Maya
Step-by-step explanation: We can convert these fractions to exact decimals 3/8 = .375 3/5 = .6 : Assign the values as follows x1 = .375; y1 = 10 x2 = .600; y2 = 14.5 : Find the slope m = y2-y1/x2-x1 m = 14.5-10/6-375 = 4.5/225 = 20 : Use the point/slope form to construct an equation: y – y1 = m(x – x1) y – 10 = 20(x – .375) y – 10 = 20x – 7.5 y = 20x – 7.5 + 10 y = 20x + 2.5, is the equation : Bucket is full when x = 1 y = 20(1) + 2.5 y = 22.5 kg for a full bucket Reply
Step-by-step explanation:
We can convert these fractions to exact decimals
3/8 = .375
3/5 = .6
:
Assign the values as follows
x1 = .375; y1 = 10
x2 = .600; y2 = 14.5
:
Find the slope m = y2-y1/x2-x1
m = 14.5-10/6-375 = 4.5/225 = 20
:
Use the point/slope form to construct an equation: y – y1 = m(x – x1)
y – 10 = 20(x – .375)
y – 10 = 20x – 7.5
y = 20x – 7.5 + 10
y = 20x + 2.5, is the equation
:
Bucket is full when x = 1
y = 20(1) + 2.5
y = 22.5 kg for a full bucket