what sum of money will earn rs 2550 intrest in 3 years, if the rate of interest is 5%/annum​

what sum of money will earn rs 2550 intrest in 3 years, if the rate of interest is 5%/annum​

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2 thoughts on “what sum of money will earn rs 2550 intrest in 3 years, if the rate of interest is 5%/annum​”

  1. [tex]\large\sf\underline{Question\::}[/tex]

    • What sum of money will earn Rs 2550 interest in 3 years if the rate of interest is 5 % per annum ?

    [tex]\large\sf\underline{Answer\::}[/tex]

    • The principal oR the sum of money on which interest for 3 years at 5 % per annum becomes Rs 2550 is [tex]\tt\blue{Rs\:17000}[/tex]

    ____________________________‎

    [tex]\large\sf\underline{Given\::}[/tex]

    • Simple interest ( SI ) = Rs 2550

    • Time ( T ) = 3 years

    • Rate of interest ( R ) = 5 % per annum

    [tex]\large\sf\underline{To\:find\::}[/tex]

    • Sum of money oR Principal ( P ) on which interest for 3 years becomes Rs 2550 .

    [tex]\large\sf\underline{Formula\:to\:be\:used\::}[/tex]

    [tex]\bf\dag[/tex] [tex]\large{\mathfrak\purple{P\:=\:\frac{SI \times 100}{R \times T}}}[/tex]

    where :

    • P = Principal

    • SI = Simple Interest

    • R = Rate

    • T = Time

    [tex]\large\sf\underline{Solution\::}[/tex]

    [tex]\sf\:Principal\:=\frac{Simple\:Interest \times 100}{Rate \times Time}[/tex]

    • Substituting the given values in the formula

    [tex]\sf\dashrightarrow\:Principal\:=\frac{2550 \times 100}{5 \times 3}[/tex]

    • Proceeding with multiplication

    [tex]\sf\dashrightarrow\:Principal\:=\frac{255000}{15}[/tex]

    • Reducing it to lower terms

    [tex]\sf\dashrightarrow\:Principal\:=\cancel{\frac{255000}{15}}[/tex]

    [tex]\sf\dashrightarrow\:Principal\:=\cancel{\frac{51000}{3}}[/tex]

    [tex]\sf\dashrightarrow\:Principal\:=\cancel{\frac{17000}{1}}[/tex]

    [tex]\small{\underline{\boxed{\mathrm\red{\dashrightarrow\:Principal\:=\:Rs\:17000}}}}[/tex] ★

    Hence ,

    • The required principal would be Rs 17000 .

    ____________________________

    [tex]\large\sf\underline{Verifying\::}[/tex]

    Not sure about the answer !?

    Let’s verify it for our self satisfaction .

    We would verify by substituting the given values and the value which we got as Principal in the formula. If we get LHS and RHS as equal , our answers must be correct.

    [tex]\sf\:Principal\:=\frac{Simple\:Interest \times 100}{Rate \times Time}[/tex]

    [tex]\sf\leadsto\:17000\:=\frac{2550 \times 100}{5 \times 3}[/tex]

    [tex]\sf\leadsto\:17000\:=\frac{255000}{15}[/tex]

    [tex]\sf\leadsto\:17000\:=\cancel{\frac{255000}{15}}[/tex]

    [tex]\sf\leadsto\:17000\:=17000[/tex]

    ‎[tex]{\sf{{\green{Hence\:verified}}}}[/tex]

    ____________________________‎

    !! Hope it helps !!

    Reply
  2. \large\sf\underline{Question\::}

    Question:

    What sum of money will earn Rs 2550 interest in 3 years if the rate of interest is 5 % per annum ?

    \large\sf\underline{Answer\::}

    Answer:

    The principal oR the sum of money on which interest for 3 years at 5 % per annum becomes Rs 2550 is \tt\blue{Rs\:17000}Rs17000

    ____________________________‎

    \large\sf\underline{Given\::}

    Given:

    Simple interest ( SI ) = Rs 2550

    Time ( T ) = 3 years

    Rate of interest ( R ) = 5 % per annum

    \large\sf\underline{To\:find\::}

    Tofind:

    Sum of money oR Principal ( P ) on which interest for 3 years becomes Rs 2550 .

    \large\sf\underline{Formula\:to\:be\:used\::}

    Formulatobeused:

    \bf\dag† \large{\mathfrak\purple{P\:=\:\frac{SI \times 100}{R \times T}}}P=

    R×T

    SI×100

    where :

    P = Principal

    SI = Simple Interest

    R = Rate

    T = Time

    \large\sf\underline{Solution\::}

    Solution:

    \sf\:Principal\:=\frac{Simple\:Interest \times 100}{Rate \times Time}Principal=

    Rate×Time

    SimpleInterest×100

    Substituting the given values in the formula

    \sf\dashrightarrow\:Principal\:=\frac{2550 \times 100}{5 \times 3}⇢Principal=

    5×3

    2550×100

    Proceeding with multiplication

    \sf\dashrightarrow\:Principal\:=\frac{255000}{15}⇢Principal=

    15

    255000

    Reducing it to lower terms

    \sf\dashrightarrow\:Principal\:=\cancel{\frac{255000}{15}}⇢Principal=

    15

    255000

    \sf\dashrightarrow\:Principal\:=\cancel{\frac{51000}{3}}⇢Principal=

    3

    51000

    \sf\dashrightarrow\:Principal\:=\cancel{\frac{17000}{1}}⇢Principal=

    1

    17000

    \small{\underline{\boxed{\mathrm\red{\dashrightarrow\:Principal\:=\:Rs\:17000}}}}

    ⇢Principal=Rs17000

    Hence ,

    The required principal would be Rs 17000 .

    ____________________________

    \large\sf\underline{Verifying\::}

    Verifying:

    Not sure about the answer !?

    Let’s verify it for our self satisfaction .

    We would verify by substituting the given values and the value which we got as Principal in the formula. If we get LHS and RHS as equal , our answers must be correct.

    \sf\:Principal\:=\frac{Simple\:Interest \times 100}{Rate \times Time}Principal=

    Rate×Time

    SimpleInterest×100

    \sf\leadsto\:17000\:=\frac{2550 \times 100}{5 \times 3}⇝17000=

    5×3

    2550×100

    \sf\leadsto\:17000\:=\frac{255000}{15}⇝17000=

    15

    255000

    \sf\leadsto\:17000\:=\cancel{\frac{255000}{15}}⇝17000=

    15

    255000

    \sf\leadsto\:17000\:=17000⇝17000=17000

    ‎{\sf{{\green{Hence\:verified}}}}Henceverified

    ____________________________‎

    !! Hope it helps !!

    Reply

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