We would verify by substituting the given values and the value which we got as Principal in the formula. If we get LHS and RHS as equal , our answers must be correct.
We would verify by substituting the given values and the value which we got as Principal in the formula. If we get LHS and RHS as equal , our answers must be correct.
[tex]\large\sf\underline{Question\::}[/tex]
[tex]\large\sf\underline{Answer\::}[/tex]
____________________________
[tex]\large\sf\underline{Given\::}[/tex]
[tex]\large\sf\underline{To\:find\::}[/tex]
[tex]\large\sf\underline{Formula\:to\:be\:used\::}[/tex]
[tex]\bf\dag[/tex] [tex]\large{\mathfrak\purple{P\:=\:\frac{SI \times 100}{R \times T}}}[/tex]
where :
[tex]\large\sf\underline{Solution\::}[/tex]
[tex]\sf\:Principal\:=\frac{Simple\:Interest \times 100}{Rate \times Time}[/tex]
[tex]\sf\dashrightarrow\:Principal\:=\frac{2550 \times 100}{5 \times 3}[/tex]
[tex]\sf\dashrightarrow\:Principal\:=\frac{255000}{15}[/tex]
[tex]\sf\dashrightarrow\:Principal\:=\cancel{\frac{255000}{15}}[/tex]
[tex]\sf\dashrightarrow\:Principal\:=\cancel{\frac{51000}{3}}[/tex]
[tex]\sf\dashrightarrow\:Principal\:=\cancel{\frac{17000}{1}}[/tex]
[tex]\small{\underline{\boxed{\mathrm\red{\dashrightarrow\:Principal\:=\:Rs\:17000}}}}[/tex] ★
Hence ,
____________________________
[tex]\large\sf\underline{Verifying\::}[/tex]
Not sure about the answer !?
Let’s verify it for our self satisfaction .
We would verify by substituting the given values and the value which we got as Principal in the formula. If we get LHS and RHS as equal , our answers must be correct.
[tex]\sf\:Principal\:=\frac{Simple\:Interest \times 100}{Rate \times Time}[/tex]
[tex]\sf\leadsto\:17000\:=\frac{2550 \times 100}{5 \times 3}[/tex]
[tex]\sf\leadsto\:17000\:=\frac{255000}{15}[/tex]
[tex]\sf\leadsto\:17000\:=\cancel{\frac{255000}{15}}[/tex]
[tex]\sf\leadsto\:17000\:=17000[/tex]
[tex]{\sf{{\green{Hence\:verified}}}}[/tex]
____________________________
!! Hope it helps !!
\large\sf\underline{Question\::}
Question:
What sum of money will earn Rs 2550 interest in 3 years if the rate of interest is 5 % per annum ?
\large\sf\underline{Answer\::}
Answer:
The principal oR the sum of money on which interest for 3 years at 5 % per annum becomes Rs 2550 is \tt\blue{Rs\:17000}Rs17000
____________________________
\large\sf\underline{Given\::}
Given:
Simple interest ( SI ) = Rs 2550
Time ( T ) = 3 years
Rate of interest ( R ) = 5 % per annum
\large\sf\underline{To\:find\::}
Tofind:
Sum of money oR Principal ( P ) on which interest for 3 years becomes Rs 2550 .
\large\sf\underline{Formula\:to\:be\:used\::}
Formulatobeused:
\bf\dag† \large{\mathfrak\purple{P\:=\:\frac{SI \times 100}{R \times T}}}P=
R×T
SI×100
where :
P = Principal
SI = Simple Interest
R = Rate
T = Time
\large\sf\underline{Solution\::}
Solution:
\sf\:Principal\:=\frac{Simple\:Interest \times 100}{Rate \times Time}Principal=
Rate×Time
SimpleInterest×100
Substituting the given values in the formula
\sf\dashrightarrow\:Principal\:=\frac{2550 \times 100}{5 \times 3}⇢Principal=
5×3
2550×100
Proceeding with multiplication
\sf\dashrightarrow\:Principal\:=\frac{255000}{15}⇢Principal=
15
255000
Reducing it to lower terms
\sf\dashrightarrow\:Principal\:=\cancel{\frac{255000}{15}}⇢Principal=
15
255000
\sf\dashrightarrow\:Principal\:=\cancel{\frac{51000}{3}}⇢Principal=
3
51000
\sf\dashrightarrow\:Principal\:=\cancel{\frac{17000}{1}}⇢Principal=
1
17000
\small{\underline{\boxed{\mathrm\red{\dashrightarrow\:Principal\:=\:Rs\:17000}}}}
⇢Principal=Rs17000
★
Hence ,
The required principal would be Rs 17000 .
____________________________
\large\sf\underline{Verifying\::}
Verifying:
Not sure about the answer !?
Let’s verify it for our self satisfaction .
We would verify by substituting the given values and the value which we got as Principal in the formula. If we get LHS and RHS as equal , our answers must be correct.
\sf\:Principal\:=\frac{Simple\:Interest \times 100}{Rate \times Time}Principal=
Rate×Time
SimpleInterest×100
\sf\leadsto\:17000\:=\frac{2550 \times 100}{5 \times 3}⇝17000=
5×3
2550×100
\sf\leadsto\:17000\:=\frac{255000}{15}⇝17000=
15
255000
\sf\leadsto\:17000\:=\cancel{\frac{255000}{15}}⇝17000=
15
255000
\sf\leadsto\:17000\:=17000⇝17000=17000
{\sf{{\green{Hence\:verified}}}}Henceverified
____________________________
!! Hope it helps !!