what sum amounts to 1044 in 4 years, at the rate of interest of 4% per annum

2 thoughts on “what sum amounts to 1044 in 4 years, at the rate of interest of 4% per annum”

1. Given :

   • Principal (P) = Rs 1044
   • Rate (R) = 4% p.a
   • Time (T) = 4years

   [tex] \\ [/tex]

   To Find :

   • Amount

   [tex] \\ [/tex]

   Solution :

   ⟹ Simple Interest = P × R × T / 100

   ⟹ Simple Interest = 1044 × 4 × 4 / 100

   ⟹ Simple Interest = 1044 × 16 / 100

   ⟹ Simple Interest = 16,704 / 100

   ⟹ Simple Interest = Rs 167.04

   Now,

   ➞ Amount = S.I + P

   ➞ Amount = 167.04 + 100

   ➞ Amount = Rs 267.04

   Thus Amount is Rs 267.04

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   ★ Additional Info :

   [tex]\small\boxed{\begin{array}{cc}\large\sf\dag \: {\underline{More \: Formulae}} \\ \\ \bigstar \: \sf{Principle :- \dfrac{SI \times 100}{R \times T}} \\ \\\bigstar \: \sf{Rate \: of \: Interest :- \dfrac{SI \times 100}{P \times T}} \\ \\ \bigstar \: \sf{Time :- \dfrac{SI \times 100}{P \times R}}\end{array}}[/tex]

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2. Given:

   • Principal = Rs. 1044

   • Rate = 4 %

   • Time = 4 years

   What To Find:

   We have to find the amount.

   Formula:

   [tex]\mathfrak{Simple \: Interest = \dfrac{Principal \times Rate \times Time}{100}}[/tex]

   [tex]\mathfrak{Amount = Principal + Simple \: Interest}[/tex]

   Solution:

   Using the formula,

   [tex]\sf{ \Longrightarrow Simple \: Interest = \dfrac{Principal \times Rate \times Time}{100}}[/tex]

   Substitute the values,

   [tex]\sf{ \Longrightarrow Simple \: Interest = \dfrac{1044 \times 4 \times 4}{100}}[/tex]

   Multiply the numerator,

   [tex]\sf{ \Longrightarrow Simple \: Interest = \dfrac{16704}{100}}[/tex]

   Divide 16704 by 100,

   [tex]\sf{ \Longrightarrow Simple \: Interest = Rs. 167.04}[/tex]

   Now add the Principal and SI,

   [tex]\sf{ \Longrightarrow Amount = Rs. \: 1044 + Rs. 167.04}[/tex]

   Add,

   [tex]\sf{ \Longrightarrow Amount = Rs. \: 1,211.04}[/tex]

   ∴ Thus, the amount is Rs. 1211.04.

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