Answer: a^3+14a^2-a-6 \begin{gathered}a^{3}-7a^{2}+12a+13-x=7a^{2}+11a+7\\\\x= 7a^{2}+11a+7-(a^{3}-7a^{2}+12a+13)\\\\x=7a^{2} +11a+7-a^{3}+7a^{2}-12a-13\\\\x=-a^{3}+14a^{2}-a-6\\\\\end{gathered} a 3 −7a 2 +12a+13−x=7a 2 +11a+7 x=7a 2 +11a+7−(a 3 −7a 2 +12a+13) x=7a 2 +11a+7−a 3 +7a 2 −12a−13 x=−a 3 +14a 2 −a−6 Reply
Answer:
a^3+14a^2-a-6
\begin{gathered}a^{3}-7a^{2}+12a+13-x=7a^{2}+11a+7\\\\x= 7a^{2}+11a+7-(a^{3}-7a^{2}+12a+13)\\\\x=7a^{2} +11a+7-a^{3}+7a^{2}-12a-13\\\\x=-a^{3}+14a^{2}-a-6\\\\\end{gathered}
a
3
−7a
2
+12a+13−x=7a
2
+11a+7
x=7a
2
+11a+7−(a
3
−7a
2
+12a+13)
x=7a
2
+11a+7−a
3
+7a
2
−12a−13
x=−a
3
+14a
2
−a−6