Answer :- Given :- Quadratic equation : x²-2x-3=0 To Find :- Discriminant Solution :- We know that, [tex]\implies\sf Discriminant = b^2 – 4ac [/tex] For the given equation :- a = 1 b = -2 c = -3 Substituting the values :- [tex]\implies\sf D = b^2 – 4ac[/tex] [tex]\implies\sf D = (-2)^2 – 4 \times 1 \times ( – 3 )[/tex] [tex]\implies\sf D = 4 + 12[/tex] [tex]\implies\sf D = 16[/tex] Value of Discriminant = 16 Reply
Given equation x²-2x-3=0 To find The value of discriminant. Answer The value of discriminant is -16. Solution On comparing the given equation with x² + bx + c = 0 Here, a = x , b = -2 and c = -3 D(discriminant) = b² – 4ac D = (-2)² – 4 × x × 3 D = -4 – 12 D = -16 ∴Hence, The value of discriminant is -16. _____________________________ Reply
Answer :-
Given :-
To Find :-
Solution :-
We know that,
[tex]\implies\sf Discriminant = b^2 – 4ac [/tex]
For the given equation :-
Substituting the values :-
[tex]\implies\sf D = b^2 – 4ac[/tex]
[tex]\implies\sf D = (-2)^2 – 4 \times 1 \times ( – 3 )[/tex]
[tex]\implies\sf D = 4 + 12[/tex]
[tex]\implies\sf D = 16[/tex]
Value of Discriminant = 16
Given
To find
Answer
The value of discriminant is -16.
Solution
On comparing the given equation with x² + bx + c = 0
Here, a = x , b = -2 and c = -3
D(discriminant) = b² – 4ac
D = (-2)² – 4 × x × 3
D = -4 – 12
D = -16
∴Hence, The value of discriminant is -16.
_____________________________