what is the ratio of number of arrangements of all letter of the word ASHOK and GEETA.​

2 thoughts on “what is the ratio of number of arrangements of all letter of the word ASHOK and GEETA.​”

1. Answer:

   Ratio

   [tex] = \frac{2}{1} [/tex]

   Step-by-step explanation:

   Arrangements:-

   1. ASHOK

   5! ways

   2. GEETA

   5! ways but E is repeating twice, so we should divide 5! by 2!

   i.e.

   [tex] \frac{5!}{2!} = \frac{5 \times 4 \times 3 \times 2!}{2!} = 5 \times 4 \times 3[/tex]

   Ratio

   [tex] \frac{5!}{5 \times 4} = \frac{5 \times 4 \times 3 \times 2 \times 1}{5 \times 4 \times 3} = \frac{2}{1} [/tex]

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2. Answer:

   Then the number of arrangements is 5! 2! Next, we have to find the ratio of the number of arrangements of the letters in the words ASHOK and GEETA

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