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Water is flowing through a cylindrical pipe of internal diameter 4 cm into a cylindrical tank
of base radius 20 cm at the r

By Jasmine

Water is flowing through a cylindrical pipe of internal diameter 4 cm into a cylindrical tank
of base radius 20 cm at the rate of 0.6 m/s. Find by how much height, the water in the tank
will rise in half an hour.​

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Jasmine

find the principal value of
[tex] { \sin( \frac{1}{ \sqrt{2} } ) }^{ – 1} [/tex]
​

7. Represent the following fractions in pictorial form.
(1 mark)
6
b.
10



I want the ans

2 thoughts on “Water is flowing through a cylindrical pipe of internal diameter 4 cm into a cylindrical tank <br /> of base radius 20 cm at the r”

  1. Answer:

    For pipe, r = 1cm Length of water flowing in 1 sec, h = 0.7m = 7cm Cylindrical Tank, R = 40 cm, rise in water level = H Volume of water flowing in 1 sec = πr2h = π x 1 x 1 x 70 = 70π Volume of water flowing in 60 sec = 70π x 60 Volume of water flowing in 30 minutes = 70π x 60 x 30 Volume of water in Tank = πr2H = π x 40 x 40 x H Volume of water in Tank = Volume of water flowing in 30 minutes π x 40 x 40 x H = 70π x 60 x 30 H = 78.75cm…

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  2. [tex]{\large{\underbrace{\textsf{\textbf{\color{red}{➵}{\color{green}{\:\:ANSWER\: :-}}}}}}}[/tex]

    ➵ For pipe, r = 1cm Length of water flowing in

    ➵ 1 sec, h = 0.7m = 7cm Cylindrical Tank, R = 40

    ➵ cm, rise in water level = H Volume of water

    ➵ flowing in 1 sec = πr2h = π x 1 x 1 x 70 = 70π

    ➵ Volume of water flowing in 60 sec = 70π x 60

    ➵ Volume of water flowing in 30 minutes = 70π

    ➵ x 60 x 30 Volume of water in Tank = πr2H = π x

    ➵ 40 x 40 x H Volume of water in Tank = Volume

    ➵of water flowing in 30 minutes π x 40 x 40 x H

    ➵ = 70π x 60 x 30 H = 78.75cm

    ㅤㅤ

    [tex]\large\mathbf\blue{HOPE\:IT\:HELPED}[/tex]

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