very that a × ( b+c) = a×b+a×c for
a= 4/5 b=-2/3 c=-1/2​

2 thoughts on “very that a × ( b+c) = a×b+a×c for<br /> a= 4/5 b=-2/3 c=-1/2​”

1. Answer:

   –14/15

   Step-by-step explanation:

   a*b+b*c

   so 4/5*—2/3+4/5*–1/2

   by solving it; –8/15+(–4/10)

   –16+(–12)/30

   Reply

2. [tex]\huge\mathcal{Given:-}[/tex]

   [tex]A = {\frac{4}{5}}[/tex]

   [tex]B = {\frac{-2}{3}}[/tex]

   [tex]C = {\frac{-1}{2}}[/tex]

   [tex]\huge\mathcal{To \:Find:-}[/tex]

   [tex] A \times (B +C) = (A× B)+(A × C)[/tex]

   [tex]\huge\mathcal\red{Solution:-}[/tex]

   [tex]\huge\mathcal{LHS}[/tex]

   [tex]\frac{4}{5} \times({\frac{-2}{3}} -{\frac{-1}{2}})[/tex]

   [tex]\mathcal\red{Taking \:out \:LCM}[/tex]

   [tex]\frac{4}{5} \times{\frac{-4-3}{6}}[/tex]

   [tex]\frac{4}{5} \times{\frac{-7}{6}}[/tex]

   [tex]\frac{-28}{30}[/tex]

   Now;

   [tex]\huge\mathcal\red{RHS}[/tex]

   [tex]{\frac{4}{5}} \times{\frac{-2}{3}} +{\frac{4}{5}} \times {\frac{-1}{2}}[/tex]

   [tex]\frac{-8}{15} + {\frac{-4}{10}}[/tex]

   [tex]\mathcal\red{Taking \:Out \:LCM}[/tex]

   [tex]\frac{-16-12}{30}[/tex]

   [tex]\frac{-28}{30}[/tex]

   [tex]\huge\mathcal{LHS=}\mathcal\red{RHS}[/tex]

   Reply