Answer: P(x) = 2x²-8 Substituting 2 at place of x, P(2) = 2(2)²-8 = 2(4)-8 = 8-8 = 0 Substituting (-2) at place of x, P(-2) = 2(-2)²-8 = 2(4)-8 = 8-8 = 0 Therefore, 2 and (-2) are the zeroes of the polynomial. Reply
Answer:
P(x) = 2x²-8
Substituting 2 at place of x,
P(2) = 2(2)²-8 = 2(4)-8 = 8-8 = 0
Substituting (-2) at place of x,
P(-2) = 2(-2)²-8 = 2(4)-8 = 8-8 = 0
Therefore, 2 and (-2) are the zeroes of the polynomial.