Verify the property ax(b+c)=(axb)+(axc) by taking: 1) a (1/3), b =0, c = (-7/6) 2)
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1 thought on “Verify the property ax(b+c)=(axb)+(axc) by taking: 1) a (1/3), b =0, c = (-7/6) 2) <br />​”

1. Step-by-step explanation:

   a(b+c)=ab+ac

   this is the distributive property

   given

   a=-10

   b=-9

   c=8

   So L.H.S.

   = a(b+c)= -10*(-9+8)=-10*(-1)=10

   => L.H.S =10•••••••••(i)

   again R.HS.

   = ab+ac = (-10)*(-9)+(-10)*8

   =90–80 =10

   => R.HS. =10••••••••••(ii)

   from (i)&(ii)

   L.H.S=R.H.S=10

   hence shown that the distributive property is true for the given numbers.

   a(b+c)=(axb)+(axc)

   L.H.S=a(b+c)

   =-10(-9+8)

   =(-10)x(-1)

   =10

   R.H.S=(axb)+(axc)

   =(-10×-9)+(-10×8)

   =90–80

   =10

   Hence proof

   L.H.S=R H S

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