Verify the identity

{a}^{3} – {b}^{3} = ( a – b)( {a}^{2} + ab \: + {b}^{2} )a3−b3=(a−b)(a2+ab+b2)

Please an

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1. Answer:

   [tex]{a}^{3} – {b}^{3} = ( a – b)( {a}^{2} + ab \: + {b}^{2} ) \\ = ( {a}^{3} + {a}^{2}b + ab {}^{2} – {a}^{2}b – ab {}^{2} – {b}^{3} ) \\ = {a}^{3} – {b}^{3} \\ \sf \: hence \: proved[/tex]

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2. [tex]{ \red{ \fbox{mark upper one Brainliest .-.}}}[/tex]

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