using repeated subtraction method find the HCF of 320,120,95​

1 thought on “using repeated subtraction method find the HCF of 320,120,95​”

1. Step-by-step explanation:

   320, 120 and 95

   _____________________________________

   Let us take 320 & 120 first m = 320,

   n = 120

   m – n = 320 – 120 = 200

   m = 200, n = 120

   ∴ m – n = 200 – 120 = 80

   120 – 80 = 40

   80 – 40 = 40

   ∴ m = w = 40 → HCF of 320, 120

   Now let us find HCF of 40 & 95

   m = 95, n = 40

   ∴ m – n = 95 – 40 = 55

   55 – 40 = 15

   40 – 15 = 25

   25 – 15 = 10

   15 – 10 = 5

   HCF of 40 & 95 is 5

   10 – 5 = 5

   HCF of 320, 120 & 95 is 5

   hope it helps you

   Reply