Universal Express traveling at 200 kmph overtakes a motorbike traveling at 68 kmph in 80 seconds. Calculate the length of Universa

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1. Given:

   Universal Express travelling at 200 kmph overtakes a motorbike travelling at 68 kmph in 80 seconds.

   To find:

   The length of Universal express.
   

   Solution:

   The speed of the Universal Express,

   s₁ = 200 km/hr = [tex]200 \times \frac{5}{18} \:m/s = 55.56\:m/s[/tex]

   The speed of the motorbike, s₂ = 68 km/hr = [tex]68 \times \frac{5}{18} \:m/s = 18.89\:m/s[/tex]

   ∴ Relative speed = s₁ – s₂ = 55.56 – 18.89 = 36.67 m/s

   The time taken to overtake, t = 80 seconds

   Let “L” meters represents the length of the Universal Express.

   We know,

   [tex]\boxed{\bold{Relative \:speed \times Time = Distance \:covered = Length \:of\: the\: train }}[/tex]

   Now, by using the above formula, we get

   The length of the Universal Express is,

   = L

   = (s₁ – s₂)t

   = [tex]36.67\: m/s \:\times 80 \:seconds[/tex]

   = [tex]\bold{2933.6\: m}[/tex]

   Thus, the length of Universal express is → 2933.6 m.

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