uf each box had 24 bottles of juice find total number of bottles brought by rakhesh​

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1. Answer:

   Given:

   Two cans contain 60 litres and 135 litres of milk respectively.

   \begin{gathered} \\ {\bf{To\: Find\::}} \\ \end{gathered}

   ToFind:

   The maximum capacity of a can which can measure the milk of each can when used an exact number of times.

   \begin{gathered} \\ {\bf{Solution\::}} \\ \end{gathered}

   Solution:

   ☛ To calculate maximum capacity of a can that measures the milk in exact number of times, we need to find H.C.F of 60 & 135.

   ⠀⠀⠀ \red\star⋆ H.C.F of 60 & 135 \red\star⋆

   \begin{gathered}{\begin{array}{r | l} 2 & 60 \\ \cline{2-2} 2 & 30 \\ \cline{2-2} 3 & 15 \\ \cline{2-2} & 5 \end{array}} \:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: {\begin{array}{r | l} 3 & 135 \\ \cline{2-2} 3 & 45 \\ \cline{2-2} 3 & 15 \\ \cline{2-2} & 5 \end{array}} \end{gathered}

   2

   \cline2−22

   \cline2−23

   \cline2−2

   60

   30

   15

   5

   3

   \cline2−23

   \cline2−23

   \cline2−2

   135

   45

   15

   5

   ➠ 60 = 2 × 2 × 3 × 5

   ➠ 135 = 3 × 3 × 3 × 5

   ✯ H.C.F of 60 & 135 = 3 × 5 = 15

   Hence,

   \begin{gathered}\dashrightarrow\:\:\bf{Max^m~ capacity~ of~ the~ can~ =~ H.C.F ~of ~60~ \& ~135~} \\ \end{gathered}

   ⇢Max

   m

   capacity of the can = H.C.F of 60 & 135

   \begin{gathered}\dashrightarrow\:\:\bf\pink{Max^m~ capacity~ of~ the~ can~ =~ 15~L} \\ \end{gathered}

   ⇢Max

   m

   capacity of the can = 15 L

   ∴ The maximum capacity of the can is 15 L

   mark me as brainliest ok

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