two vertices of a triangle are a(-4,4) b( 6,12) and centroid is g(0,6) find coordinates of third vertex c and show that ar (ABC) =3 ar (AGB) [ step by step explanation]
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Two vertices of ΔABC are A(-1, 4) and B(5, 2) and its centroid is G(0, -3). Then, the coordinates of C are. ∴x=-4andy=-15. So, the coordinates of C are (-4, -15).
Two vertices of ΔABC are A(-1, 4) and B(5, 2) and its centroid is G(0, -3). Then, the coordinates of C are. ∴x=-4andy=-15. So, the coordinates of C are (-4, -15).
Two vertices of ΔABC are A(-1, 4) and B(5, 2) and its centroid is G(0, -3). Then, the coordinates of C are. ∴x=-4andy=-15. So, the coordinates of C are (-4, -15).
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Two vertices of ΔABC are A(-1, 4) and B(5, 2) and its centroid is G(0, -3). Then, the coordinates of C are. ∴x=-4andy=-15. So, the coordinates of C are (-4, -15).