Two positive integers ‘a’ and ‘b’ can be expressed as a = x 3 y 2 and b = xy3 x and y are prime numbers .What is the L.C.M and H.C.F of a and b? (CBSE 2019) About the author Aaliyah
Answer: Given: a = x3y2 = X x X x X x Y x Y and b = xy3 = X x Y x Y x Y where a and b are positive integers and x and y are prime numbers. So, the LCM of a and b will be x3y3 . Now , H.C.F Given that, a =x3y2 = x × x × x × y × y and b = xy3 = x × y × y × y ∴ HCF of a and b = HCF (x3y2,xy3) = x × y × y = xy2 [Since, HCF is the product of the smallest power of each common prime factor involved in the numbers] HOPE THIS HELP YOU !!!!!!! Reply
Answer:
Given:
a = x3y2
= X x X x X x Y x Y
and
b = xy3
= X x Y x Y x Y
where a and b are positive integers and x and y are prime numbers.
So,
the LCM of a and b will be x3y3 .
Now , H.C.F
Given that,
a =x3y2 = x × x × x × y × y
and b = xy3 = x × y × y × y
∴ HCF of a and b = HCF (x3y2,xy3)
= x × y × y
= xy2
[Since, HCF is the product of the smallest power of each common prime factor involved in the numbers]
HOPE THIS HELP YOU !!!!!!!
Answer:
sorry i don’t know the answer of this question