Two point charges repel with a force of 4.5 milli Newton . On doubling on of the charges and altering their separation by 5 cm, th

Question

Two point charges repel with a force of 4.5 milli Newton . On doubling on of the charges and altering their separation by 5 cm, the force of repulsion is 1.6 milli Newton. What was their original separation *
1 point
20 cm
25 cm
40 cm
50 cm
Answer needed ASAP

Julia · Answer

Answer:   20 cm   Explanation:   please mark me brainliest answer

Cora · Answer

Explanation:   F= Kq1q2/r^2    1.6= kq^2 /9    Since k= 9x10^9    1.6= 10^9xq^2    q= 4x10^-5 C    Hope it helps.

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