Two line segments AB and CD bisect each other at point O. Prove that:(a) AAOC = ABOD.(b) AC = BD About the author Piper
Answer:AB and CD bisect each other at O i.e, AO=BO and CO=DO in ΔCOA and ΔDOB Given CO=OD,∠COA=∠BOD [ vertically opp angles] AD=BD ∴ΔCOA≅ΔBOD (i) ∴AC=BD[C.P.CT] (ii) ∠CAB=∠ABD[C.P.CT] again in ΔCOB and ΔAOD CO=OD [given] BO=AO [given] ∠COB=∠AOD [vertically opp angles] ∴ΔCOB≅ΔAOD ∴∠CBA=∠BAD [ C.P. C.T] (iii) and so AD∣∣CD [ ∵∠CBA=∠BAD which are altanate angles] and AD= Step-by-step explanation: Reply
Answer:AB and CD bisect each other at O i.e, AO=BO and CO=DO
in ΔCOA and ΔDOB
Given CO=OD,∠COA=∠BOD [ vertically opp angles]
AD=BD
∴ΔCOA≅ΔBOD
(i) ∴AC=BD[C.P.CT]
(ii) ∠CAB=∠ABD[C.P.CT]
again
in ΔCOB and ΔAOD
CO=OD [given]
BO=AO [given]
∠COB=∠AOD [vertically opp angles]
∴ΔCOB≅ΔAOD
∴∠CBA=∠BAD [ C.P. C.T]
(iii) and so AD∣∣CD [ ∵∠CBA=∠BAD which are altanate angles]
and AD=
Step-by-step explanation: