. Two identical metallic cubes of side 5cm are melted to form a solid cylinder of radius 7cm. What will be the height of the cylin

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. Two identical metallic cubes of side 5cm are melted to form a solid cylinder of radius 7cm. What will be the height of the cylinder so formed? (use π=22/7)​

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  1. Answer:

    Given:

    Height (h) of cylindrical part = height (h) of the conical part =7 cm

    Diameter of the cylindrical part =12 cm

    Therefore, Radius (r) of the cylindrical part =

    2

    12

    =6 cm

    So, Radius of the conical part =6 cm

    Slant height (l) of conical part =

    r

    2

    +h

    2

    cm

    =

    6

    2

    +7

    2

    =

    36+49

    =

    85

    ≈9.22 cm.

    The total surface area of the remaining solid = CSA of the cylindrical part + CSA of the conical part + Base area of the circular part

    =2πrh+πrl+πr

    2

    =2×

    7

    22

    ×6×7+

    7

    22

    ×6×9.22+

    7

    22

    ×6×6

    =264+173.86+113.14

    =551 cm

    2

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