two cycles were bought at same cost.one was sale at profit of 15% and another was sold at loss of 10%.if the difference in seeling

two cycles were bought at same cost.one was sale at profit of 15% and another was sold at loss of 10%.if the difference in seeling prise is ₹200,find the cost of the cycles​

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  1. Step-by-step explanation:

    Let c.p of one be x

    The c.p of other be. y

    S.p of first=x(120/100)=6x/5

    S.p of other=y(80/100)=4y/5

    Total c.p=x+y

    Total s.p=(6x+4y)/5

    6x/5=4y/5 (given)=3x=2y

    Now c.p=x+3x/2=5x/2

    S.p=(6x+6x)/5=12x/5

    Loss=c.p-s.p=20 (given)

    5x/2-12x/5=20

    X/10=20

    X=₹200

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