two coins are tossed simultaneously find the probability getting
no tail?
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2 thoughts on “two coins are tossed simultaneously find the probability getting <br /> no tail?<br />​”

1. Answer:

   Let E5 = event of getting no tail. Then, E5 = {HH} and, therefore, n(E5) = 1. Therefore, P(getting no tail) = P(E5) = n(E5)/n(S) = ¼.

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2. Answer:

   1/4 chance

   Step-by-step explanation:

   plss markbranilest

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