Two Biased coins are thrown together. On one of the coins head appears twice as frequently as tail on the other for every 2 times that head appears, tail appear s 3 times. The probability that the coins show both heads or both tail is ??
2 thoughts on “Two Biased coins are thrown together. On one of the coins head appears <br />twice as frequently as tail on the other for every 2”
ADDITIONALINFORMATION:–
When we toss two coins simultaneously then the possible of outcomes are: (two heads) or (one head and one tail) or (two tails) i.e., in short (H, H) or (H, T) or (T, T) respectively; where H is denoted for head and T is denoted for tail.
When we toss two coins simultaneously then the possible of outcomes are: (two heads) or (one head and one tail) or (two tails) i.e., in short (H, H) or (H, T) or (T, T) respectively; where H is denoted for head and T is denoted for tail.Therefore, total numbers of outcome are 22 = 4
When we toss two coins simultaneously then the possible of outcomes are: (two heads) or (one head and one tail) or (two tails) i.e., in short (H, H) or (H, T) or (T, T) respectively; where H is denoted for head and T is denoted for tail.Therefore, total numbers of outcome are 22 = 4The above explanation will help us to solve the problems on finding the probability of tossing two coins.
SOLUTION:–
When two different coins are tossed randomly, the sample space is given by
When two different coins are tossed randomly, the sample space is given byS = {HH, HT, TH, TT}
When two different coins are tossed randomly, the sample space is given byS = {HH, HT, TH, TT}Therefore, n(S) = 4.
getting two heads:
Let E1 = event of getting 2 heads. Then,E1 = {HH} and, therefore,
When we toss two coins simultaneously then the possible of outcomes are: (two heads) or (one head and one tail) or (two tails) i.e., in short (H, H) or (H, T) or (T, T) respectively; where H is denoted for head and T is denoted for tail.
ADDITIONAL INFORMATION:–
When we toss two coins simultaneously then the possible of outcomes are: (two heads) or (one head and one tail) or (two tails) i.e., in short (H, H) or (H, T) or (T, T) respectively; where H is denoted for head and T is denoted for tail.
When we toss two coins simultaneously then the possible of outcomes are: (two heads) or (one head and one tail) or (two tails) i.e., in short (H, H) or (H, T) or (T, T) respectively; where H is denoted for head and T is denoted for tail.Therefore, total numbers of outcome are 22 = 4
When we toss two coins simultaneously then the possible of outcomes are: (two heads) or (one head and one tail) or (two tails) i.e., in short (H, H) or (H, T) or (T, T) respectively; where H is denoted for head and T is denoted for tail.Therefore, total numbers of outcome are 22 = 4The above explanation will help us to solve the problems on finding the probability of tossing two coins.
SOLUTION:–
When two different coins are tossed randomly, the sample space is given by
When two different coins are tossed randomly, the sample space is given byS = {HH, HT, TH, TT}
When two different coins are tossed randomly, the sample space is given byS = {HH, HT, TH, TT}Therefore, n(S) = 4.
Let E1 = event of getting 2 heads. Then, E1 = {HH} and, therefore,
n(E1) = 1.
Therefore, P(getting 2 heads) = P(E1) = n(E1)/n(S) = 1/4.
Answer:
See below
Step-by-step explanation:
When we toss two coins simultaneously then the possible of outcomes are: (two heads) or (one head and one tail) or (two tails) i.e., in short (H, H) or (H, T) or (T, T) respectively; where H is denoted for head and T is denoted for tail.