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The work done in a moving particle once around the circle – + = 1:2 = 0
under the force field F = Mi + N) = cos y 1 + x (1 –

By Abigail

The work done in a moving particle once around the circle – + = 1:2 = 0
under the force field F = Mi + N) = cos y 1 + x (1 – siny) j is given by
Given
1: use Green s theorem)
BE​

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Abigail

what is catalyst ?
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Any guess ki m kon hu jo pehchanega sirf wahi answer dega​

if one root of equation 2x square 3x – 2 = 0 is 1/2 then other root is​

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