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The value of x for which 3x,(x+8) and (5x+2) are three
consecutive terms of an A.P. is​

By Serenity

The value of x for which 3x,(x+8) and (5x+2) are three
consecutive terms of an A.P. is​

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Serenity

4. Observe the figure and answer the following questions. 4m
1. Name the pairs of opposite angles .
2. Name the pair

find the coordinates of the point which divided segment ab into four equal parts if a(-5.7) b(-3 -1)​

1 thought on “The value of x for which 3x,(x+8) and (5x+2) are three<br />consecutive terms of an A.P. is​”

  1. Step-by-step explanation:

    Given:–

    3x,(x+8) and (5x+2) are three consecutive terms of an A.P.

    To find:–

    Find the value of x ?

    Solution:–

    Method-1:–

    Given that

    3x,(x+8) and (5x+2) are three consecutive terms of an A.P.

    Since they are in the AP then the common difference is same.

    =>Common difference = tn – t(n-1)

    => (x+8)-(3x) = (5x+2)-(x+8)

    =>x+8-3x = 5x+2-x-8

    => 8-2x = 4x-6

    => 8+6 = 4x+2x

    => 14 = 6x

    => 6x = 14

    => x = 14/6

    => x = 7/3

    Therefore,x=7/3

    Method-2:–

    Given that

    3x,(x+8) and (5x+2) are three consecutive terms of an A.P.

    We know that

    a,b,c are the three consecutive terms in an AP then 2b = a+c

    we have

    a = 3x

    b=x+8

    c=5x+2

    => 2(x+8) = 3x+5x+2

    => 2x+16 = 8x+2

    => 16-2 = 8x-2x

    => 14 = 6x

    => 6x = 14

    => x = 14/6

    => x = 7/3

    Therefore,x=7/3

    Answer:–

    The value of x for the given problem is 7/3

    Used formulae:–

    1.Common difference in an AP = tn – t(n-1)

    2.a,b,c are the three consecutive terms in an AP then 2b = a+c or b = (a+c)/2

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