The time taken by the car to reach 90 km/hr. from rest to 5 minutes. Calculate a) The acceleration of the car. b) The distance covered by the car. don’t spam About the author Adalyn
Answer: Explanation: a) 0.0833 m/sec² , b) 3.75 km The time taken by the car to reach 90 km/hr. from rest to 5 minutes. Given, t = 5 min = 5 x 60 = 300 sec final velocity v = 90 km/ hr = 90 x 1000/3600 m/sec = 25 m/sec initial velocity u = 0 a) we know v = u + a t where a is the acceleration. so we can calculate acceleration as, a = (v-u) / t or, a = (25-0)/300 m/sec² = 0.0833 m/sec². b) Let the distance covered by the car is s, so we have the formula: s = ut + 1/2 a t² or, s = 0 x 300 + 1/2 x 0.0833 x (300)² s = 3750 m = 3.75 km. Reply
Answer:
Explanation: a) 0.0833 m/sec² , b) 3.75 km
The time taken by the car to reach 90 km/hr. from rest to 5 minutes.
Given,
t = 5 min = 5 x 60 = 300 sec
final velocity v = 90 km/ hr = 90 x 1000/3600 m/sec = 25 m/sec
initial velocity u = 0
a) we know v = u + a t where a is the acceleration.
so we can calculate acceleration as, a = (v-u) / t
or, a = (25-0)/300 m/sec² = 0.0833 m/sec².
b) Let the distance covered by the car is s,
so we have the formula: s = ut + 1/2 a t²
or, s = 0 x 300 + 1/2 x 0.0833 x (300)²
s = 3750 m = 3.75 km.