The time taken by a person to cover 150 km was 2. 1/2 hours more than the time taken in the return
journey. If he returned

The time taken by a person to cover 150 km was 2. 1/2 hours more than the time taken in the return
journey. If he returned at a speed of 10 km/hour more than the speed while going, find the speed per
hour in each direction.​

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  1. Step-by-step explanation:

    ⇒ Distance given =150km

    ⇒ Let the forward speed be x and the return speed will be x+10

    We know that, Time=

    speed

    Distance

    x

    150

    =

    x+10

    150

    +2.5

    ⇒ 150(x+10)−150x=2.5×x(x+10)

    ⇒ 150x+1500−150x=2.5x

    2

    +25x

    ⇒ 2.5x

    2

    +25x−1500=0

    ⇒ 25x

    2

    +250x−15000=0

    ⇒ x

    2

    +10x−600=0

    ⇒ x

    2

    +30x−20x−600=0

    ⇒ x(x+30)−20(x+30)=0

    ⇒ (x+30)(x−20)=0

    The value of cannot be negative.

    ∴ Forward speed will be 20km/hr

    ⇒ Return speed =20+10=30km/hr

    ⇒ The required product =20×30=600km/hr

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