The time taken by a person to cover 150 km was 2. 1/2 hours more than the time taken in the return journey. If he returned at a speed of 10 km/hour more than the speed while going, find the speed per hour in each direction. About the author Serenity
Step-by-step explanation: ⇒ Distance given =150km ⇒ Let the forward speed be x and the return speed will be x+10 We know that, Time= speed Distance ∴ x 150 = x+10 150 +2.5 ⇒ 150(x+10)−150x=2.5×x(x+10) ⇒ 150x+1500−150x=2.5x 2 +25x ⇒ 2.5x 2 +25x−1500=0 ⇒ 25x 2 +250x−15000=0 ⇒ x 2 +10x−600=0 ⇒ x 2 +30x−20x−600=0 ⇒ x(x+30)−20(x+30)=0 ⇒ (x+30)(x−20)=0 The value of cannot be negative. ∴ Forward speed will be 20km/hr ⇒ Return speed =20+10=30km/hr ⇒ The required product =20×30=600km/hr Reply
Step-by-step explanation:
⇒ Distance given =150km
⇒ Let the forward speed be x and the return speed will be x+10
We know that, Time=
speed
Distance
∴
x
150
=
x+10
150
+2.5
⇒ 150(x+10)−150x=2.5×x(x+10)
⇒ 150x+1500−150x=2.5x
2
+25x
⇒ 2.5x
2
+25x−1500=0
⇒ 25x
2
+250x−15000=0
⇒ x
2
+10x−600=0
⇒ x
2
+30x−20x−600=0
⇒ x(x+30)−20(x+30)=0
⇒ (x+30)(x−20)=0
The value of cannot be negative.
∴ Forward speed will be 20km/hr
⇒ Return speed =20+10=30km/hr
⇒ The required product =20×30=600km/hr