The sum of three consecutive multiples of 12 is 324. What are the multiples? About the author Isabella
Answer: let the number be x-12 x and x+12 sum =324 3x=324 x=108 is the first number 120 is the second number 96 is the third number Step-by-step explanation: hope this has help you Reply
Answer: Step-by-step explanation: Let the first consecutive multiple be 12x. Then we get, 12x + 12(x+1) + 12(x+2) = 324 36x + 36 = 324 36(x+1) = 324 x+1 = 9 x = 8 So the required numbers are as follows 12 x 8 = 96 12 x (8 + 1) = 108 12 x (8+2) = 120 Hope this helps Mark as brainliest Reply
Answer:
let the number be x-12
x and x+12 sum =324
3x=324
x=108 is the first number
120 is the second number
96 is the third number
Step-by-step explanation:
hope this has help you
Answer:
Step-by-step explanation:
Let the first consecutive multiple be 12x. Then we get,
12x + 12(x+1) + 12(x+2) = 324
36x + 36 = 324
36(x+1) = 324
x+1 = 9
x = 8
So the required numbers are as follows
12 x 8 = 96
12 x (8 + 1) = 108
12 x (8+2) = 120
Hope this helps
Mark as brainliest