The sum of the first 10 natural numbers is
a)54 d) 55 c] 65 d)85​

2 thoughts on “The sum of the first 10 natural numbers is<br />a)54 d) 55 c] 65 d)85​”

1. Answer:

   55 is the correct answer of this question

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2. Answer:

   The series of first 10 natural numbers is an arithmetic progressions with first tern as 1 and common difference 1.

   So the sum of the series will be Sn = n/2 { 2a+ ( n-1 ) d } where n is the number of terms in the series, a is the first term and d is the common difference.

   S10 = 10 / 2 { 2 ( 1 ) + ( 10 -1 ) 1 }

   = 5 ( 2+9)

   = 5 ( 11 )

   = 55

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