the sum of the digits of a two digits number is 15. if the number formed by reversing the digits is less than the original number by 27, then find the original number About the author Remi
Answer: 96 Step-by-step explanation: Let the unit’s place=x Then the ten’s place=15−x ∴ original number=10(15−x)+x=150−10x+x=150−9x By reversing the digits, we get New number=10x+(15−x)=10x+15−x=9x−15 According to the problem, original number−New number=27 ⇒150−9x−9x+15=27 ⇒−18x+165=27 ⇒−18x=27−165=−108 ⇒x= −18 −108 =6 Hence original number=150−9x=150−9×6=150−54=96 Reply
Step-by-step explanation:
96 is the right answer of this question
Answer:
96
Step-by-step explanation:
Let the unit’s place=x
Then the ten’s place=15−x
∴ original number=10(15−x)+x=150−10x+x=150−9x
By reversing the digits, we get
New number=10x+(15−x)=10x+15−x=9x−15
According to the problem,
original number−New number=27
⇒150−9x−9x+15=27
⇒−18x+165=27
⇒−18x=27−165=−108
⇒x=
−18
−108
=6
Hence original number=150−9x=150−9×6=150−54=96