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The sum of first p, q, r terms of an appointment are a, b,,c respectively. Show that a/q(q-r)+b/q(r-p)+c/r(p-q)=0

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The sum of first p, q, r terms of an appointment are a, b,,c respectively. Show that a/q(q-r)+b/q(r-p)+c/r(p-q)=0

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Alice

how could you tell that something else was produced besides just the rust?

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