Answer: Given AP is 5+8+11+,,,,,,,,,, a=5,d=8-5=3 Sn=n/2(2a+(n-1)d) S10=10/2(2(5)+9(3)) =5(10+27) =5(37) =185 the sum of first 10 terms of an arithmetic progression 5+8+11+,,,,,,,,,,is 185 Reply
Answer:
Given AP is 5+8+11+,,,,,,,,,,
a=5,d=8-5=3
Sn=n/2(2a+(n-1)d)
S10=10/2(2(5)+9(3))
=5(10+27)
=5(37)
=185
the sum of first 10 terms of an arithmetic progression 5+8+11+,,,,,,,,,,is 185
and I am not sure if it was so much they were all the