The sum of a two digits number and the number obtained by reversing the order of its digits is 121, and the digits differ by 3. find the numbers. About the author Remi
[tex]\Huge\sf\mathbb\color{red}\underline{\colorbox{blue}{Answer}}[/tex] Let no at ones= x Let no. at tens=10(x+3) =10x+ 30 New no. Let no. at ones place x+3 let no. ta tens place 10x 10x +30+x + 10x + x +3= 121 22x=88 x=88/22 x=4 the original no. is 74 the new no. is 47 please❀ Mark me Brainlist please❀ Reply
Answer:
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Step-by-step explanation:
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[tex]\Huge\sf\mathbb\color{red}\underline{\colorbox{blue}{Answer}}[/tex]
Let no at ones= x
Let no. at tens=10(x+3)
=10x+ 30
New no.
Let no. at ones place x+3
let no. ta tens place 10x
10x +30+x + 10x + x +3= 121
22x=88
x=88/22
x=4
the original no. is 74
the new no. is 47
please❀ Mark me Brainlist please❀